aidez moi svp je suis en galère c'est de la factorisation niveaux 3 ème
Mathématiques
dzo
Question
aidez moi svp je suis en galère c'est de la factorisation niveaux 3 ème
2 Réponse
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1. Réponse Anonyme
bonsoir
b) 22 a + 55 b - 11 = 11 ( 2 a + 5 b)
c) 42 x + 35 = 7 ( 6 x + 5)
d) 5 x² + x = x ( 5 x + 1)
f) 40 a + 24 b = 8 ( 5 a + 3 b)
g) 5 x² + 35 x = 5 x (x + 7)
i) ( 7 x + 3) ( 8 x - 1) + ( 7 x + 3) ( x + 4)
= ( 7 x + 3) ( 8 x - 1 + x + 4) = ( 7 x + 3) ( 9 x+ 3)
j) ( 9 x - 1) ( 4 x + 2) - ( 2 x + 3) ( 9 x - 1)
= ( 9 x - 1) ( 4 x + 2 - 2 x - 3) = ( 9 x - 1) ( 2 x - 1)
k) ( 2 x + 1)² + ( 2 x + 1) ( x - 9) = (2 x + 1) ( 2 x + 1 + x - 9)
= ( 2 x + 1) ( 3 x - 8) -
2. Réponse MonsieurFirdown
Bonsoir
B = 22a+55b-11
B = 11(2a+5b)
C = 42x+35
C = 7×6x + 7×5
C = 7(6x+5)
D = 5x²+x
D = x×5x +x×1
D = x(5x+1)
F = 40a+24b
F = 8×5a + 8×3b
F = 8(5a+3b)
G = 5x²+35x
G = 5x×x + 5x×7
G = 5x(x+7)
I = (7x+3)(8x-1)+(7x+3)(x+4)
I = (7x+3)[(8x-1)(x+4)]
I = (7x+3)(8x- 1+x+4)
I = (7x+3)(9x+3)
J = (9x-1) (4x+2)-(2x+3) (9x-1)
J = (9x1)[(4x+2)-(2x+3)]
J = (9x-1) (4x+2-2x-3)
J = (9x-1)(2x-1)
K = (2x+1)²+(2x+1)(x-9)
K = (2x+1)[(2x+1)(x-9)]
K = (2x+1)(2x+1+x-9)
K = (2x+1)(3x-8)
Voilà ^^