Mathématiques

Question

Bonjour j'ai besoin de l'aide pour ce devoir de 3e Merci

1)Développer et réduire
A=(3x+2)²
B=2x-(7x-2)²
C=(y+6)(y-6)
D=(-2x+5)(4x-3)

2) Factoriser si possible
E=x²-8x+16
F=x²-7x+49
G=9x²-48x+64
H=81-x²
I=(x-4)(x-7)+(x-4)(2x-5)
J=(x+2)²-9

1 Réponse

  • Bonsoir,

    1) développer :

    A = (3x + 2)^2
    A = (3x)^2 + 2 * 3x * 2 + 2^2
    A = 9x^2 + 12x + 4

    B = 2x - (7x - 2)^2
    B = 2x - (49x^2 - 28x + 4)
    B = 2x - 49x^2 + 28x - 4
    B = -49x^2 + 30x - 4

    C = (y + 6)(y - 6)
    C = (a + b)(a - b) = a^2 - b^2
    C = y^2 - 36

    D = (-2x + 5)(4x - 3)
    D = -8x^2 + 6x + 20x - 15
    D = -8x^2 + 26x - 15

    2) factoriser :

    E = x^2 - 8x + 16
    E = (x)^2 - 2 * x * 4 + (4)^2
    E = (x - 4)^2

    F = x^2 - 7x + 49
    F = pas factorisable

    G = 9x^2 - 48x + 64
    G = (3x)^2 - 2 * 3x * 8 + (8)^2
    G = (3x - 8)^2

    H = 81 - x^2
    H = (9)^2 - (x)^2
    H = (9 - x)(9 + x)

    I = (x - 4)(x - 7) + (x - 4)(2x - 5)
    I = (x - 4)(x - 7 + 2x - 5)
    I = (x - 4)(3x - 12)
    I = (x - 4) * 3(x - 4)
    I = 3(x - 4)^2

    J = (x + 2)^2 - 9
    J = (x + 2)^2 - (3)^2
    J = (x + 2 - 3)(x + 2 + 3)
    J = (x - 1)(x + 5)

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