bonjour , aider mois soit E=4x^2-9-(2x+3)(x-1) developper et reduire E factoiriser E . merciiiiiiiiiiiii

bonsoir

E=4x*-9-(2x+3)(x-1)
= 4x*-9-[2x*-2x+3x-3]
= 4x*-9-2x*+2x-3x+3]
= 2x*-x-6
factoriser

E=4x*-9-(2x+3)(x-1)
E= (2x)*-3*-(2x+3)(x-1)
E= (2x-3)(2x+3)-(2x+3)(x-1)
E= (2x+3)(2x-3-x+1)
E= (2x+3)(x-2)

Bonjour

E = 4x² - 9 - (2x + 3) (x - 1)
= 4x² - 9 - (2x * x + 2x * (-1) + 3 * x + 3 * (-1))
= 4x² - 9 - (2x² - 2x + 3x - 3)
= 4x² - 9 - (2x² + x - 3)
= 4x² - 9 - 2x² - x + 3
= 2x² - x - 6

E = 4x² - 9 - (2x + 3) (x - 1)
= (2x)² - 3² - (2x + 3) (x - 1)
= (2x - 3) (2x + 3) - (2x + 3) (x - 1)
= (2x + 3) [ (2x - 3) - (x - 1) ]
= (2x + 3) (2x - 3 - x + 1)
= (2x + 3) (x - 2)

Voilà j'espère avoir pu t'aider ^^