Bonjour Je voudrais de l'aide pour le 2eme exercice svp

Bonjour ;

a)

[tex]5-(x- 3) = 4x-(3x-8)\\\\ \Rightarrow 5 - x +3=4x-3x+8 \\\\ \Rightarrow 8-x = x + 8 \\\\ \Rightarrow 0 = 2x \\\\ \Rightarrow x = 0 .[/tex]

b)

[tex]2 +x -(5+2x)-7 = 3x + 7 \\\\ \Rightarrow 2+x-5-2x-7 = 3x + 7 \\\\ \Rightarrow -x - 10 = 3x + 7 \\\\ \Rightarrow -17 = 4x \\\\ \Rightarrow x = - \dfrac{17}{4} .[/tex]

c)

[tex]5(x-1)+3(2-x)=0 \\\\ \Rightarrow 5x-5+6-3x = 0 \\\\ \Rightarrow 2x +1 =0 \\\\ \Rightarrow 2x = -1 \\\\ \Rightarrow x = - \dfrac{1}{2} .[/tex]

d)

[tex]7(x+4)-3(x+2)=x+7 \\\\ \Rightarrow 7x+28-3x-6 = x+7 \\\\ \Rightarrow 4x+22 = x+7 \\\\ \Rightarrow 3x=-15 \\\\ \Rightarrow x = -5 .[/tex]

e)

[tex]2(x-1)-3(x+1)=4(x-2) \\\\ \Rightarrow 2x-2-x-3 = 4x-8 \\\\ \Rightarrow -x-5 = 4x - 5 \Rightarrow 3 = 5x \\\\ \Rightarrow x = \dfrac{3}{5} .[/tex]

f)

[tex]8(4-3x)+1=53-3(x-5) \\\\ \Rightarrow 32-24x+1=53-3x+15 \\\\ \Rightarrow -24x+33 = -3x +68 \\\\ \Rightarrow -35 = 21x \\\\ \Rightarrow x= - \dfrac{35}{21} \\\\ \Rightarrow x= - \dfrac{5}{3} .[/tex]