Bonjour, quelqu’un pourrait me dériver cette formule ? Merci F(x) = (5x+11)/(x^2+3)

bonjour,
f(x)=(5x+11)(x²+3)
f(x)= (5x)(x²)+(11)(x²)+(5x)(3)+(11)(+3)
f(x)=5x³+11x²+15x+33
f'(x)=15x²+22x+15

f(x) = (5x+11)/(x²+3)

→ f’(x) = ((u’v)-(uv’))/v²

or u=5x+11 u’=5
v=x²+3 v’=2x

donc f’(x) = ((5*(x²+3))-(5x+11)*2x)/(x²+3)²

f’(x) = (5x²+15-(10x²+22x))/(x²+3)²

f’(x) = (5x²+15-10x²-22x)/(x²+3)²

f’(x) = (-5x ²-22x+15)/(x²+3)²